By symmetry the electric field will be radial. So, if we apply Gauss's Law to a cylinder with radius $r$ and length $d$ whose axis is along the wire, we obtain

$\begin{align*}E \cdot 2 \pi r d = \frac{Q_{\text{enclosed}}}{\epsilon_0} = \frac{\lambda d}{\epsilon_0} \Longrightarrow E = \...$
Therefore, answer (A) is correct.

Solution to 2008 Problem 17